[
binary search
interactive
]
Leetcode 0278 First Bad Version
Problem statement
https://leetcode.com/problems/first-bad-version/
Solution
Just do binary search in O(log n)
complexity
Complexity
It is O(log n)
for time and O(1)
for space.
Code
class Solution:
def firstBadVersion(self, n):
beg, end = 1, n
while beg < end:
mid = (beg + end)//2
if isBadVersion(mid):
end = mid
else:
beg = mid + 1
return beg