[
linked list
]
BinarySearch 0942 Replace Linked List on Index
Problem statement
https://binarysearch.com/problems/Replace-Linked-List-on-Index/
Solution
Equal to Leetcode 1669. Merge In Between Linked Lists, but with some border cases.
Complexity
It is O(m + n)
for time and O(1)
for additional space.
Code
class Solution:
def solve(self, a, b, lo, hi):
start, temp, tempb = a, a, b
for ind in range(hi + 1):
if ind == lo - 1: start = temp
temp = temp.next
while tempb.next: tempb = tempb.next
start.next, tempb.next = b, temp
return a if lo else a.next