[
accumulate
array
]
BinarySearch 0816 List Partitioning with Inequality Relation
Problem statement
https://binarysearch.com/problems/List-Partitioning-with-Inequality-Relation/
Solution
Equal to Leetcode 0915 Partition Array into Disjoint Intervals.
Complexity
It is O(n)
for time and space.
Code
class Solution:
def solve(self, A):
t1 = list(accumulate(A, max))
t2 = list(accumulate(A[::-1], min))[::-1]
for i in range(1, len(A)):
if t1[i-1] <= t2[i]: return i