[
array
queue
sort
simulation
]
BinarySearch 0186 Ascending Cards
Problem statement
https://binarysearch.com/problems/Ascending-Cards/
Solution
Equal to Leetcode 0950. Reveal Cards In Increasing Order.
Complexity
It is O(n log n)
for time and O(n)
for space.
Code
class Solution:
def solve(self, deck):
n = len(deck)
idx = deque(range(n))
ans = [-1] * n
for card in sorted(deck):
ans[idx.popleft()] = card
if idx: idx += [idx.popleft()]
return ans