[
sort
greedy
]
BinarySearch 0053 Create Largest Number From a List
Problem statement
https://binarysearch.com/problems/Create-Largest-Number-From-a-List/
Solution
Equal to Leetcode 0179. Largest Number.
Complexity
It is O(n log n)
for time and O(n)
for space.
Code
class Solution:
def solve(self, nums):
strs = [str(x) for x in nums]
compare = lambda a, b: -1 if a+b > b+a else 1 if a+b < b+a else 0
return "".join(sorted(strs, key = cmp_to_key(compare)))