Leetcode 0217. Contains Duplicate

Problem statement

https://leetcode.com/problems/contains-duplicate/

Solution

In python just create set and check that length of this set is equal to the original length, oneliner.

Complexity

Complexity, both time and memory is O(n).

Code

class Solution:
    def containsDuplicate(self, nums):
        return len(set(nums)) != len(nums)