[
math
string
groupby
]
BinarySearch 0449 Number of Unique Character Substrings
Problem statement
https://binarysearch.com/problems/Number-of-Unique-Character-Substrings/
Solution
Equal to Leetcode 1180 Count Substrings with Only One Distinct Letter.
Complexity
It is O(n)
for time and space.
Code
class Solution:
def solve(self, s):
lens = [len(list(j)) for i, j in groupby(s)]
return sum(i*(i+1)//2 for i in lens)