Problem statement

https://binarysearch.com/problems/Palindromic-Anagram/

Solution

All we need to do is to counte elements and we can have only one of them with odd frequency.

Complexity

It is O(n) for time and O(26) for space.

Code

class Solution:
    def solve(self, s):
        return sum(i%2 == 1 for i in Counter(s).values()) <= 1